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Find the number which is as much greater than 84 as it is less than 108.
A92
B94
C96
D98
Answer & Solution
Correct answer: C. 96
1. The required number is equidistant from 84 and 108.
2. The equidistant value is the average: (84 + 108)/2.
3. This equals 192/2 = 96.
_Source: RRB Group D (RRC) PYQ, held 27-10-2013, Q.57._
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