If a solute has valency factor $x$, then normality $N$ is related to molarity $M$ by
A$N = \dfrac{M}{x}$
B$N = xM$
C$N = x + M$
D$N = \dfrac{x}{M}$
Answer & Solution
Correct answer: B. $N = xM$
The formula sheet states that normality $= x \times$ molarity, where $x$ is the valency factor or change in oxidation number. Therefore $N=xM$.
Related questions
The mass of NaOH (M = 40 g/mol) required to prepare 500 mL of a 0.20 M NaOH solution isWhich of these solutions will boil at the highest temperature at 1 atm?The molality of a 1 M aqueous NaCl solution (density = 1.04 g/mL, NaCl M = 58.5 g/mol) is Osmotic pressure π of a dilute solution obeys π = C R T. Here C representsVan't Hoff factor i > 1 for a solute indicatesA negative deviation from Raoult law is expected whenIf a solute dimerises in solution, its observed molar mass compared with the calculated vaWhich of the following is NOT a colligative property?