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If a solute has valency factor $x$, then normality $N$ is related to molarity $M$ by
A$N = \dfrac{M}{x}$
B$N = xM$
C$N = x + M$
D$N = \dfrac{x}{M}$
Answer & Solution
Correct answer: B. $N = xM$
The formula sheet states that normality $= x \times$ molarity, where $x$ is the valency factor or change in oxidation number. Therefore $N=xM$.
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