alleryFor gases only, the molecular weight is given in the notes by
A$\text{Molecular weight} = \text{V.D.}$
B$\text{Molecular weight} = \dfrac{\text{V.D.}}{2}$
C$\text{Molecular weight} = 2 \times \text{V.D.}$
D$\text{Molecular weight} = 22.4 \times \text{V.D.}$
Answer & Solution
Correct answer: C. $\text{Molecular weight} = 2 \times \text{V.D.}$
**The formula list states:** Mol. Wt.
$= \text{V.D.} \times 2$ for gases only.
**Hence molecular weight is twice the vapour density.**
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