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Equal heat is given to two objects A and B, each of mass 1 g. The temperature of A rises by 3 °C while that of B rises by 5 °C. The ratio of the specific heat of A to that of B is:
A3 : 5
B5 : 3
C1 : 1
D15 : 1
Answer & Solution
Correct answer: B. 5 : 3
1. Same heat: $Q = m c_A \Delta T_A = m c_B \Delta T_B$.
2. Masses are equal, so $c_A \Delta T_A = c_B \Delta T_B$.
3. Rearrange: $\dfrac{c_A}{c_B} = \dfrac{\Delta T_B}{\Delta T_A} = \dfrac{5}{3}$.
4. The smaller temperature rise means larger specific heat, so 3 : 5 is the inverted trap and is rejected.
_Source: Balbharati (Maharashtra Board) Class 10 Science & Technology, Ch 5 "Heat", p.81_
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