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How much heat energy is required to raise the temperature of 5 kg of water from 20 °C to 100 °C? (Specific heat of water = 1 kcal/kg °C)
A200 kcal
B500 kcal
C400 kcal
D100 kcal
Answer & Solution
Correct answer: C. 400 kcal
1. Heat absorbed: $Q = m \times c \times \Delta T$.
2. Temperature change: $\Delta T = 100 - 20 = 80\ ^\circ C$.
3. Substitute: $Q = 5\ \text{kg} \times 1\ \text{kcal/kg}\,^\circ C \times 80\,^\circ C$.
4. $Q = 400\ \text{kcal}$.
_Source: Balbharati (Maharashtra Board) Class 10 Science & Technology, Ch 5 "Heat", p.78_
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