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A tungsten bulb on a 220 V supply draws a current of 0.45 A. What is its power rating?
A9.9 W
B99 W
C220 W
D489 W
Answer & Solution
Correct answer: B. 99 W
1. Power is potential difference times current: $P = V \times I$.
2. Substitute $V = 220$ V, $I = 0.45$ A: $P = 220 \times 0.45$.
3. $P = 99$ W.
_Source: Balbharati (Maharashtra Board) Class 10 Science & Technology, Ch 4 "Effects of Electric Current", p.60_
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