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The total revenue (in Rupees) from selling $x$ units is $R(x)=3x^2+36x+5$. The marginal revenue when $x=15$ is

A₹ 90
B₹ 96
C₹ 116
D₹ 126
Answer & Solution
Correct answer: D. ₹ 126
1. Marginal revenue $=\dfrac{dR}{dx}=6x+36$. 2. At $x=15$: $6(15)+36=90+36=126$. 3. The trap $90$ forgets the constant term $36$. _Source: syllabus Mathematics Ch 6 "Application of Derivatives", p.5_
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