Home › ISC Class 12 › Mathematics › Application of Derivatives › The total revenue (in Rupees) from selling $x$ u…
The total revenue (in Rupees) from selling $x$ units is $R(x)=3x^2+36x+5$. The marginal revenue when $x=15$ is
A₹ 90
B₹ 96
C₹ 116
D₹ 126
Answer & Solution
Correct answer: D. ₹ 126
1. Marginal revenue $=\dfrac{dR}{dx}=6x+36$.
2. At $x=15$: $6(15)+36=90+36=126$.
3. The trap $90$ forgets the constant term $36$.
_Source: NCERT Class 12 Mathematics Ch 6 "Application of Derivatives", p.5_
Related questions
Elasticity of demand is given byProfit is maximised whereMarginal revenue (MR) for a price-taking firm (perfect competition) equalsMarginal cost (MC) isTwo numbers have a sum of $24$. Their product is largest when the numbers areFor $f(x)=3x^4-8x^3+12x^2-48x+25$ on $[0,3]$, the critical point inside the interval isA cylindrical tank of radius $10$ m is filled with wheat at $314$ m$^3$/h. The depth of thThe maximum value of $[x(x-1)+1]^{1/3}$ for $0\le x\le 1$ is