For the conversion of X to Y following second order kinetics with rate = k[X]^2, if [X] is increased to three times, by what factor does the rate of formation of Y change?

1. Rate $= k[X]^2$. 2. New rate $= k(3[X])^2 = 9k[X]^2$. 3. So the rate increases by a factor of $3^2 = 9$. 4. Distractor A treats it as first order; distractor D treats it as third order. _Source: NCERT Class 12 Chemistry Ch 3 "Chemical Kinetics", p.10_