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The current sensitivity of a moving coil galvanometer (deflection per unit current) is:
Ak / NAB
BNAB / k
CNAB / (kR)
DNABk
Answer & Solution
Correct answer: B. NAB / k
1. From equilibrium, $\phi = \dfrac{NAB}{k}I$.
2. Current sensitivity is defined as the deflection per unit current, $\dfrac{\phi}{I}$.
3. Dividing gives $\dfrac{\phi}{I} = \dfrac{NAB}{k}$.
4. The factor $1/R$ appears in voltage sensitivity, not current sensitivity.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", p.160_
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