Two long parallel wires a distance d apart carry currents Iₐ and I_b. The magnitude of the force per unit length between them is:
Aμ₀ Iₐ I_b d / (2π)
Bμ₀ Iₐ I_b / (2d)
Cμ₀ Iₐ I_b / (4πd)
Dμ₀ Iₐ I_b / (2πd)
Answer & Solution
Correct answer: D. μ₀ Iₐ I_b / (2πd)
1. Field of wire a at wire b: $B_a = \dfrac{\mu_0 I_a}{2\pi d}$.
2. Force on length $L$ of wire b: $F = I_b L B_a = \dfrac{\mu_0 I_a I_b}{2\pi d}L$.
3. Force per unit length: $f = \dfrac{F}{L} = \dfrac{\mu_0 I_a I_b}{2\pi d}$.
4. The $1/2d$ form omits the $\pi$ from the straight-wire field and is incorrect.
_Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", p.155_
Keep practising Moving Charges and Magnetism
Browse all Moving Charges and Magnetism questions for ISC Class 12, or explore more Physics topics.
Related questions
The magnetic field at a distance $r$ from a LONG STRAIGHT wire carrying current $I$ isThe magnetic force on a charge $q$ moving with velocity $\vec{v}$ in a magnetic field $\veMatch the magnetism termWork done by a magnetic forceNEET · Physics · Magnetic Formula ↔ QuantityA bismuth bar near a strong magnet on the lab table is:Materials are classified by which quantity?Magnetic field lines of a bar magnet form: