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Two long parallel wires a distance d apart carry currents Iₐ and I_b. The magnitude of the force per unit length between them is:

Aμ₀ Iₐ I_b d / (2π)
Bμ₀ Iₐ I_b / (2d)
Cμ₀ Iₐ I_b / (4πd)
Dμ₀ Iₐ I_b / (2πd)
Answer & Solution
Correct answer: D. μ₀ Iₐ I_b / (2πd)
1. Field of wire a at wire b: $B_a = \dfrac{\mu_0 I_a}{2\pi d}$. 2. Force on length $L$ of wire b: $F = I_b L B_a = \dfrac{\mu_0 I_a I_b}{2\pi d}L$. 3. Force per unit length: $f = \dfrac{F}{L} = \dfrac{\mu_0 I_a I_b}{2\pi d}$. 4. The $1/2d$ form omits the $\pi$ from the straight-wire field and is incorrect. _Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", p.155_
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