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HomeISC Class 12PhysicsMoving Charges and Magnetism › The proportionality constant μ₀/4π in the Biot–S…

The proportionality constant μ₀/4π in the Biot–Savart law has the exact SI value:

A9 × 10⁹ T m A⁻¹
B10⁷ T m A⁻¹
C4π × 10⁻⁷ T m A⁻¹
D10⁻⁷ T m A⁻¹
Answer & Solution
Correct answer: D. 10⁻⁷ T m A⁻¹
1. The permeability of free space is $\mu_0 = 4\pi \times 10^{-7}$ T m A⁻¹. 2. The Biot–Savart constant is $\dfrac{\mu_0}{4\pi}$. 3. Dividing: $\dfrac{4\pi\times10^{-7}}{4\pi} = 10^{-7}$ T m A⁻¹. 4. The $4\pi\times10^{-7}$ option is $\mu_0$ itself, not $\mu_0/4\pi$. _Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", p.144_
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