Start learning →

The proportionality constant μ₀/4π in the Biot–Savart law has the exact SI value:

A9 × 10⁹ T m A⁻¹
B10⁷ T m A⁻¹
C4π × 10⁻⁷ T m A⁻¹
D10⁻⁷ T m A⁻¹
Answer & Solution
Correct answer: D. 10⁻⁷ T m A⁻¹
1. The permeability of free space is $\mu_0 = 4\pi \times 10^{-7}$ T m A⁻¹. 2. The Biot–Savart constant is $\dfrac{\mu_0}{4\pi}$. 3. Dividing: $\dfrac{4\pi\times10^{-7}}{4\pi} = 10^{-7}$ T m A⁻¹. 4. The $4\pi\times10^{-7}$ option is $\mu_0$ itself, not $\mu_0/4\pi$. _Source: syllabus Physics Ch 4 "Moving Charges and Magnetism", p.144_
Practise this question with Quill — ISC Class 12 →

Keep practising Moving Charges and Magnetism

Browse all Moving Charges and Magnetism questions for ISC Class 12, or explore more Physics topics.

Start a Moving Charges and Magnetism lesson →