The trajectory equation of a projectile shows that its path is a
Astraight line
Bcircle
Cparabola
Dhyperbola
Answer & Solution
Correct answer: C. parabola
The trajectory has the form $y=x\tan\theta-\dfrac{1}{2}\dfrac{g}{(v_0\cos\theta)^2}x^2$, which is quadratic in $x$. A quadratic relation between $y$ and $x$ represents a parabola.
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