A charged particle is at rest in a region of uniform magnetic field B. The magnetic force acting on it is:

1. The magnetic force is $\mathbf{F} = q(\mathbf{v} \times \mathbf{B})$. 2. Its magnitude is $F = qvB\sin\theta$, which depends on the speed $v$. 3. For a charge at rest, $|\mathbf{v}| = 0$, so $F = 0$. 4. Only a moving charge experiences a magnetic force. _Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", p.135_