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The table of displacement, velocity, and acceleration graphs includes a case of motion with constant velocity. In that case, which combination of graph features is correct?
Adisplacement–time graph is horizontal, velocity–time graph is horizontal at zero, acceleration–time graph is horizontal at zero
Bdisplacement–time graph is a straight line with constant slope, velocity–time graph is horizontal, acceleration–time graph is horizontal at zero
Cdisplacement–time graph is curved upward, velocity–time graph is a rising straight line, acceleration–time graph is horizontal above zero
Ddisplacement–time graph is a straight line with changing slope, velocity–time graph is curved, acceleration–time graph is nonzero constant
Answer & Solution
Correct answer: B. displacement–time graph is a straight line with constant slope, velocity–time graph is horizontal, acceleration–time graph is horizontal at zero
For constant velocity, position changes linearly with time, so the displacement–time graph is a straight line of constant slope. The velocity remains constant, giving a horizontal velocity–time graph, and the acceleration is zero, so the acceleration–time graph lies along zero.
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