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A man walks 3 km South, then 4 km West. Shortest distance from start is

A7 km only
B5 km
C1 km only
D12 km only
Answer & Solution
Correct answer: B. 5 km
1. Vertical displacement 3 km south, horizontal 4 km west. 2. Diagonal = sqrt(9 + 16) = sqrt(25) = 5 km. 3. Hence option A. _Source: jkchrome.com SSC Distance and Direction PDF (Mistral OCR), section on distance via Pythagoras_
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