The ratio of **octahedral voids** to **atoms** in a close-packed structure is:
A1 : 1
B2 : 1
C1 : 2
D3 : 1
Answer & Solution
Correct answer: A. 1 : 1
Per atom in fcc/hcp: 1 octahedral void. NaCl structure exploits this — Cl⁻ in fcc lattice, Na⁺ in all octahedral voids → 1:1 stoichiometry, CN = 6.
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