The ratio of **tetrahedral voids** to **atoms** in a close-packed structure (fcc or hcp) is:
A1 : 1
B2 : 1
C1 : 2
D3 : 1
Answer & Solution
Correct answer: B. 2 : 1
In any close-packed structure (fcc/hcp), per atom in the lattice there are 2 tetrahedral voids and 1 octahedral void. Used in classifying ionic compounds (NaCl fcc lattice, etc.).
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