Water rises 4 cm in a capillary of radius 0.5 mm. If the same capillary is dipped in a liquid of half the surface tension and twice the density (same contact angle), water now rises by:
A4 cm
B2 cm
C1 cm
D8 cm
Answer & Solution
Correct answer: C. 1 cm
$h \propto T/\rho$. New $T = T/2$, new $\rho = 2\rho$ ⇒ new $h = h \times (1/2)/(2) = h/4 = 4/4 = 1$ cm.
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