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In a torch circuit the cell pushes current of 0.3 A through a bulb of 8 ohm. The voltage of the cell is
A2.4 V
B0.04 V
C8.3 V
D26.7 V
Answer & Solution
Correct answer: A. 2.4 V
1. Use V = I R.
2. I = 0.3 A and R = 8 ohm.
3. V = 0.3 * 8 = 2.4 V.
4. So the cell voltage is 2.4 V.
_Source: Selina Concise Physics Class 9, Ch 9 Current Electricity (Mistral OCR'd PDF), section on Ohm's law_
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