Two friends start at the same point. A walks 3 km east, then 4 km north. B walks 4 km east, then 3 km north. The distance between them now is:
A0 km across all cases
B5 km
Cabout 1.4 km
D7 km
Answer & Solution
Correct answer: C. about 1.4 km
1. A ends at (3, 4) from start; B ends at (4, 3).
2. Difference vector = (4-3, 3-4) = (1, -1).
3. Distance = sqrt(1^2 + (-1)^2) = sqrt(2).
4. = 1.414 km.
5. So they are about 1.4 km apart.
_Source: SSC CGL Reasoning (Direction Sense), standard PYQ patterns_
Related questions
Facing north, a man turns 135° clockwise, then 180°. Which direction is he facing now?A car travels 30 km north, then 40 km east. Distance from the start?Anu walks 10 m south, then 7 m west, then 4 m north, then 7 m east. How far is she from thA man walks 5 km east, turns left and walks 3 km, turns left again and walks 5 km. How farA man walks 5 km north, turns right and walks 3 km, turns right and walks 5 km. How far frA and B start from point X. A goes 5 km north, then 12 km east. B goes 13 km east directlyIn the same ground, who is to the south-east of the person to the left of D?In the same ground (above), minimum distance between C and E (m)?