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On reacting 50 mL ethanol with excess conc. H2SO4 at 443 K, the main product is:
AEthanal
BDiethyl ether
CEthanoic acid
DEthene
Answer & Solution
Correct answer: D. Ethene
1. Conc. H2SO4 at 443 K acts as a strong dehydrating agent.
2. Ethanol loses one water molecule per molecule of ethanol.
3. The dehydration product is ethene (CH2=CH2).
4. At a lower temperature near 413 K the product would be diethyl ether instead.
5. So at 443 K the main product is ethene.
_Source: NCERT Class 10 Science Ch 4 'Carbon and its Compounds' (byjus.com extract)_
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