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Identify the product of the reaction: 2C2H5OH + 2Na ->
A2C2H5Na + 1/2 O2
B2C2H5ONa + H2
CC4H10 + 2NaOH
D2CH3CHO + 2NaH
Answer & Solution
Correct answer: B. 2C2H5ONa + H2
1. Sodium reacts with ethanol like it does with water but more slowly.
2. The acidic -OH proton is displaced and hydrogen gas is released.
3. Sodium replaces the hydrogen of -OH, forming sodium ethoxide.
4. Net: 2C2H5OH + 2Na -> 2C2H5ONa + H2 (gas).
5. So the products are sodium ethoxide and hydrogen gas.
_Source: NCERT Class 10 Science Ch 4 'Carbon and its Compounds' (byjus.com extract)_
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