A body accelerates from 5 m per second to 25 m per second over 4 seconds. The distance covered is:
A40 m
B100 m
C80 m
D60 m
Answer & Solution
Correct answer: D. 60 m
1. Use the average-velocity form: s = ((u + v) / 2) × t.
2. Given u = 5 m per second, v = 25 m per second, t = 4 s.
3. Average velocity = (5 + 25) / 2 = 15 m per second.
4. Displacement = 15 × 4 = 60 m.
5. Option A uses initial velocity only; option C uses final velocity only; option D double-counts.
_Source: Selina Concise Physics ICSE Class 9, Ch 2 'Motion in One Dimension' (aplustopper.com extract)_
Keep practising Motion in One Dimension
Browse all Motion in One Dimension questions for ICSE Class 9, or explore more Physics topics.
Related questions
Order the steps to find final velocityJudge these motion graph claimsPick the bigger answer each roundMatch each motion equation to its useSort scalars from vectorsA stone is thrown straight up with initial velocity 20 m per second. Taking g = 10 m per sA body has zero average velocity over an interval. Which conclusion is FORCED?A stone is dropped from rest. After 2 seconds its velocity is approximately: