Home › ICSE Class 9 › physics › Motion in One Dimension › A body accelerates from 5 m per second to 25 m p…
A body accelerates from 5 m per second to 25 m per second over 4 seconds. The distance covered is:
A40 m
B100 m
C80 m
D60 m
Answer & Solution
Correct answer: D. 60 m
1. Use the average-velocity form: s = ((u + v) / 2) × t.
2. Given u = 5 m per second, v = 25 m per second, t = 4 s.
3. Average velocity = (5 + 25) / 2 = 15 m per second.
4. Displacement = 15 × 4 = 60 m.
5. Option A uses initial velocity only; option C uses final velocity only; option D double-counts.
_Source: Selina Concise Physics ICSE Class 9, Ch 2 'Motion in One Dimension' (aplustopper.com extract)_
Related questions
A stone is thrown straight up with initial velocity 20 m per second. Taking g = 10 m per sA car at 36 km/h is brought to rest by uniform retardation in 50 metres. The retardation mA body has zero average velocity over an interval. Which conclusion is FORCED?A stone is dropped from rest. After 2 seconds its velocity is approximately:On a velocity-time graph, the area under the curve represents:A car decelerates uniformly from 20 m per second to rest in 4 seconds. The retardation is:On a displacement-time graph, what does the slope of the line represent?Which equation gives displacement in terms of initial velocity, acceleration and time?