Home › CBSE Class 8 › mathematics › linearequations › Solve for z: 3(5z − 7) − 2(9z − 11) = 4(8z − 13)…
Solve for z: 3(5z − 7) − 2(9z − 11) = 4(8z − 13) − 17
Az = 1
Bz = 2
Cz = 3
Dz = −2
Answer & Solution
Correct answer: B. z = 2
Expand: LHS = 15z − 21 − 18z + 22 = −3z + 1. RHS = 32z − 52 − 17 = 32z − 69. So −3z + 1 = 32z − 69, giving 35z = 70 and z = 2.
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