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The equation of a plane parallel to x + 2y - 3z = 5 and passing through (1, 1, 1) is
Ax + 2y - 3z = 5
Bx + 2y + 3z = 0
Cx + 2y - 3z = 0
D3x + 6y - 9z = 5
Answer & Solution
Correct answer: C. x + 2y - 3z = 0
1. Parallel planes share the same normal; the equation has form x + 2y - 3z = k.
2. Substitute the given point: 1 + 2 - 3 = k.
3. So k = 0.
4. The equation is x + 2y - 3z = 0.
_Source: NCERT Class 12 Maths Part 2 Ch 11 "Three Dimensional Geometry", §11.6.2_
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