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A long solenoid has 1000 turns per metre and carries 2 A. The magnetic field strength inside is
Aμ₀ × 10³ T
Bμ₀ × 10⁶ T
Cμ₀ × 4 × 10³ T
Dμ₀ × 2 × 10³ T
Answer & Solution
Correct answer: D. μ₀ × 2 × 10³ T
1. Inside an ideal long solenoid: B = μ₀ n I.
2. Given n = 1000 turns/m, I = 2 A.
3. Substitute: B = μ₀ × 1000 × 2 = μ₀ × 2 × 10³.
4. Numerically: B = (4π × 10⁻⁷)(2 × 10³) ≈ 2.51 × 10⁻³ T.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", §4.8.1_
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