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The current sensitivity of a moving coil galvanometer with N turns, coil area A, magnetic field B, spring constant k is
ANAB/k
Bk/(NAB)
CN²AB/k
DNABk
Answer & Solution
Correct answer: A. NAB/k
1. From equilibrium: kϕ = NIAB.
2. Current sensitivity is defined as deflection per unit current: ϕ/I.
3. Rearrange: ϕ/I = NAB/k.
4. Higher N, larger A, stronger B, or weaker spring constant k all raise sensitivity.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", §4.11_
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