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A 0.5 m wire carrying 2 A is placed perpendicular to a 0.4 T magnetic field. The force on the wire is
A0.2 N
B0.4 N
C2.5 N
D4.0 N
Answer & Solution
Correct answer: B. 0.4 N
1. The force on a current-carrying wire in a perpendicular field is F = BIL.
2. Given B = 0.4 T, I = 2 A, L = 0.5 m.
3. Substitute: F = 0.4 × 2 × 0.5.
4. F = 0.4 N. So option B.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", §4.2.3_
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