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In a crossed E and B velocity selector, a charged particle of speed v passes undeflected when v equals
AEB
BB/E
CE/B
DE + B
Answer & Solution
Correct answer: C. E/B
1. The selector arranges E and B perpendicular to each other and to v.
2. Electric force qE and magnetic force qvB act in opposite directions.
3. For no net deflection: qE = qvB, which simplifies to E = vB.
4. Solve for v: v = E/B. Particles faster or slower than this value are deflected.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", §4.4.1_
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