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A charged particle moves with velocity v parallel to a uniform magnetic field B. The magnetic force on the particle is
AqvB
Bzero
Cqv/B
DqB/v
Answer & Solution
Correct answer: B. zero
1. The magnetic force on a moving charge is F = qv × B.
2. The magnitude is F = qvB sin θ, where θ is the angle between v and B.
3. When v is parallel to B, θ = 0° so sin θ = 0.
4. Therefore F = 0; a charge moving along the field experiences no magnetic force.
_Source: NCERT Class 12 Physics Ch 4 "Moving Charges and Magnetism", §4.2.2_
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