Which compound will give a POSITIVE IODOFORM test (yellow $\mathrm{CHI_3}$ precipitate with $\mathrm{I_2}$/NaOH)?

1. The iodoform test (NCERT §8.4) is positive for compounds containing the $\mathrm{CH_3{-}CO{-}}$ group (methyl ketone) OR a group oxidisable to that fragment. 2. The classic positive substrates: acetone ($\mathrm{CH_3COCH_3}$ — has methyl ketone directly), acetaldehyde ($\mathrm{CH_3CHO}$), and any RCO-$\mathrm{CH_3}$ ketone. 3. Also positive: ethanol ($\mathrm{CH_3CH_2OH}$) and any RCH(OH)-$\mathrm{CH_3}$ secondary alcohol, because $\mathrm{I_2}$/NaOH OXIDISES them first to the corresponding methyl ketone or acetaldehyde. 4. NEGATIVE: methanol (no $\mathrm{CH_3CO{-}}$ generable), formaldehyde (no methyl carbon to iodinate), benzaldehyde (no $\alpha$-methyl), all higher alcohols other than the second-carbon-methyl pattern. 5. So ethanol AND acetone — option A — is the correct combined answer. _Source: NCERT Class 12 Chemistry Part 2, Ch 8, §8.4 (Haloform reaction / iodoform test), p. 13–14._