The c.d.f. $F(x)$ of the p.d.f. $f(x) = 3x^2$ for $0 < x < 1$ is:
A$3x$
B$6x$
C$x^3$
D$1/(3x^2)$
Answer & Solution
Correct answer: C. $x^3$
$F(x) = \int_0^x 3t^2\,dt = [t^3]_0^x = x^3$ for $0 \leq x \leq 1$.
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