If $f(x) = 1/5$ for $0 \leq x \leq 5$ (uniform distribution) is the p.d.f. of waiting time for a bus, then the probability of waiting more than 4 minutes is:
A$1/4$
B$3/5$
C$1/5$
D$4/5$
Answer & Solution
Correct answer: C. $1/5$
$P[X > 4] = \int_4^5 (1/5)\,dx = 1/5 = 0.20$.
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