For the probability distribution $P[X=0]=0.1$, $P[X=1]=k$, $P[X=2]=2k$, $P[X=3]=2k$, $P[X=4]=k$, find $k$.
A0.25
B0.20
C0.1
D0.15
Answer & Solution
Correct answer: D. 0.15
Total probability = 1: $0.1 + k + 2k + 2k + k = 1$ ⇒ $6k = 0.9$ ⇒ $k = 0.15$.
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