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The F₂ **genotypic** ratio in Mendel's monohybrid cross is:
A3:1
B1:2:1 (TT : Tt : tt)
C1:1
D9:3:3:1
Answer & Solution
Correct answer: B. 1:2:1 (TT : Tt : tt)
Genotypic ratio in F₂ = **1:2:1** (1 TT : 2 Tt : 1 tt). The 3:1 phenotype ratio collapses Tt (intermediate genotype) with TT (homozygote dominant) because both look 'tall'.
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