If a tower 30 m tall casts a shadow of 30 m, the angle of elevation of the sun is:

To find the angle of elevation of the sun, we represent the situation as a right-angled triangle where: 1. **Height of the tower ($h$):** $30 \text{ m}$ (Opposite side to the angle $\theta$) 2. **Length of the shadow ($s$):** $30 \text{ m}$ (Adjacent side to the angle $\theta$) 3. **Angle of elevation:** $\theta$ We use the trigonometric ratio for tangent: $$\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}$$ Substituting the given values: $$\tan(\theta) = \frac{30}{30}$$ $$\tan(\theta) = 1$$ To find $\theta$, we take the inverse tangent: $$\theta = \tan^{-1}(1)$$ Since $\tan(45^\circ) = 1$, the angle of elevation is: $$\theta = 45^\circ$$ Thus, the correct option is **45°**.