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In a series circuit with R1 = 4 Ω and R2 = 6 Ω, total resistance is:

A2 Ω
B24 Ω
C10 Ω
D2.4 Ω
Answer & Solution
Correct answer: C. 10 Ω
**Series resistors add:** R_total = R1 + R2 = 4 + 6 = 10 Ω. Same current flows through both.
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