For the cell Zn | Zn²⁺ || Cu²⁺ | Cu at 298 K, the Nernst equation expresses E_cell as:
AE°_cell − (0.059/2) log ([Zn²⁺]/[Cu²⁺])
BE°_cell − (0.059) log ([Zn²⁺]/[Cu²⁺])
CE°_cell + (0.059/2) log ([Zn²⁺]/[Cu²⁺])
DE°_cell − (0.059/2) log ([Cu²⁺]/[Zn²⁺])
Answer & Solution
Correct answer: A. E°_cell − (0.059/2) log ([Zn²⁺]/[Cu²⁺])
Cell reaction: Zn + Cu²⁺ → Zn²⁺ + Cu, n=2. Q = [Zn²⁺]/[Cu²⁺] (products/reactants for ions only). So **E = E° − (0.059/2) log([Zn²⁺]/[Cu²⁺])**.
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