alleryThe momentum of a photon of wavelength $\lambda$ is
A$p=\dfrac{h}{\lambda}$
B$p=h\lambda$
C$p=\dfrac{hc}{\lambda}$
D$p=\dfrac{\lambda}{h}$
Answer & Solution
Correct answer: A. $p=\dfrac{h}{\lambda}$
For a photon, energy $E=h\nu$ and also $E=pc$.
Therefore $p=E/c=h\nu/c$.
Since $\nu=c/\lambda$, this becomes $p=h/\lambda$.
**Option C is energy, not momentum.**
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