In the standard electrode potential series, F₂/F⁻ has E° = +2.87 V and Li⁺/Li has E° = −3.05 V. Which of the following is correct?

High +ve E° → strong tendency to gain electrons → strong **oxidising agent** (F₂). Most −ve E° → strong tendency to lose electrons → strong **reducing agent** (Li metal). Note: Li ranks lower than Cs in IE alone, but in aqueous solution Li is the strongest reducing agent due to its very high hydration enthalpy.