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Raoult's law for an ideal solution of two volatile components states:
A$p_{total} = p_1° + p_2°$ (sum of pure pressures)
B$p_{total} = p_1°x_1 + p_2°x_2$ (mole-weighted)
C$p_{total} = (p_1° + p_2°) / 2$ (average)
D$p_{total} = p_1° × p_2°$ (product)
Answer & Solution
Correct answer: B. $p_{total} = p_1°x_1 + p_2°x_2$ (mole-weighted)
RAOULT'S LAW (ideal): total vapour pressure = sum of (pure-component vapour pressure × mole fraction). p_total = p1° × x1 + p2° × x2. Holds when solute-solvent interactions resemble pure-component interactions.
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