For a binomial distribution B(n, p), the MEAN and VARIANCE are:
AMean = p, Variance = np
BMean = np, Variance = np(1−p)
CMean = np², Variance = n²p
DMean = n+p, Variance = n×p
Answer & Solution
Correct answer: B. Mean = np, Variance = np(1−p)
Binomial B(n, p): mean = np; variance = np(1−p) = npq.
For p = 0.5 and n = 10: mean = 5, variance = 2.5.
Keep practising Relations, Functions & Inverse Trigonometry
Browse all Relations, Functions & Inverse Trigonometry questions for AP Intermediate 2nd Year, or explore more Mathematics topics.
Related questions
Complete the rule about restricting a domain$\tan^{-1}\left(\tfrac{1}{2}\right) + \tan^{-1}\left(\tfrac{1}{3}\right)$ equalsAll real $x$ satisfying $ in^{-1}(x) + in^{-1}(1-x) = \cos^{-1}(x)$ are$\displaystyle um_{n=1}^{\infty} \tan^{-1}\left(\frac{1}{n^2 + n + 1}\right)$ equalsTrue or false: the historical noteTrue or false: principal valuesDomain checkMatch each inverse function to its principal value branch