alleryThe **oxidation state of Fe** in $K_4[Fe(CN)_6]$ is:
A+1
B+2
C+3
D+4
Answer & Solution
Correct answer: B. +2
**Charge balance:** 4(+1) + [Fe + 6(-1)] = 0
We have ⇒ Fe + (-6) = -4 ⇒ Fe.
So ⇒ Fe + (-6) = **+2**.
K₄[Fe(CN)₆] is potassium ferrocyanide.
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