In a single-slit diffraction setup, slit width 0.2 mm, screen distance 2 m. First minimum is observed at 5 mm from the central maximum. The wavelength of light is:
A500 nm
B550 nm
C5000 Å (= 500 nm)
DBoth A and C
Answer & Solution
Correct answer: D. Both A and C
First minimum: $y = D\lambda/a$. So $\lambda = ya/D = (5\times10^{-3})(0.2\times10^{-3})/2 = 5 \times 10^{-7}$ m = 500 nm = 5000 Å.
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