A telescope objective has diameter 2.5 m. Its angular resolution at $\lambda = 5500$ Å is approximately:
A$2.7 \times 10^{-7}$ rad (~0.06 arcsec)
B$2.7 \times 10^{-3}$ rad
C$1.0$ arcsec
D$5.5 \times 10^{-10}$ rad
Answer & Solution
Correct answer: A. $2.7 \times 10^{-7}$ rad (~0.06 arcsec)
$\theta = 1.22\lambda/D = 1.22 \times 5.5 \times 10^{-7}/2.5 \approx 2.68 \times 10^{-7}$ rad ≈ 0.06 arcsec. Larger apertures give better angular resolution.
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