Two slits 0.5 mm apart are illuminated with light of 600 nm. The fringes are observed on a screen 1 m away. The fringe width is:
A0.6 mm
B1.2 mm
C1.5 mm
D3 mm
Answer & Solution
Correct answer: B. 1.2 mm
$w = \lambda D/d = (600 \times 10^{-9})(1)/(0.5 \times 10^{-3}) = 1.2 \times 10^{-3}$ m = 1.2 mm.
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