Start learning →

In Young's double-slit experiment, the fringe width $w$ is given by:

A$w = \lambda d / D$
B$w = \lambda D / d$
C$w = D / (\lambda d)$
D$w = (\lambda + D)/d$
Answer & Solution
Correct answer: B. $w = \lambda D / d$
Fringe width (separation between adjacent maxima or minima) $w = \lambda D/d$, where $D$ = screen-slit distance, $d$ = slit separation, $\lambda$ = wavelength. Bigger $\lambda$ or $D$, or smaller $d$ ⇒ wider fringes.
Practise this question with Quill — AP Intermediate 2nd Year →

Keep practising Dual Nature of Radiation and Matter

Browse all Dual Nature of Radiation and Matter questions for AP Intermediate 2nd Year, or explore more Physics topics.

Start a Dual Nature of Radiation and Matter lesson →
Related questions
However intense the light, no emission occurs below the:The minimum energy needed to free an electron from a metal is its:Order the photoelectric storyPhotoelectric current falls to zero at which voltage?The de Broglie relation contains a wave concept together with a:The momentum carried by a photon of wavelength $\lambda$ isSet by intensity or by frequency?The de Broglie wavelength of a fast electron is comparable with: