alleryThe sum of 5 consecutive integers is always divisible by:
A$5$
B$3$
C$7$
D$11$
Answer & Solution
Correct answer: A. $5$
Sum of n consecutive integers from k to k+(n-1) = n(2k + n - 1)/2. For n = 5: sum = 5(2k+4)/2 = 5(k+2), always divisible by 5. This is a GMAT DS structural fact.
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