alleryThe **wavelength** of light of wavelength 600 nm in air becomes (in water, n = 1.33) approximately:
A~451 nm
B~600 nm
C~798 nm
D~452 μm
Answer & Solution
Correct answer: A. ~451 nm
$\lambda_{med} = \lambda_0/n = 600/1.33 \approx 451$ nm.
Wavelength shortens in a denser medium; frequency stays the same.
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