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A triangle has sides 5, 12 and 13. The radius of its inscribed circle (inradius) is:

A$2$
B$3$
C$2.5$
D$1$
Answer & Solution
Correct answer: A. $2$
Right triangle (5² + 12² = 13² = 169). Area = ½ × 5 × 12 = 30. Semiperimeter s = (5 + 12 + 13)/2 = 15. Inradius r = Area/s = 30/15 = 2.
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